#include <stdio.h>



int main()
{
    int i;
    for(i = 0;;i++)
    {
        if(((i*8+7)*8+1)*8+1 == (34*i+15)*17+4)
        {
            printf("The required number is:%d\n",(34*i+15)*17+4);
            break;
        }
    }


    return 0;
}

//熊贤豪